Question
Download Solution PDFWetted perimeter of a regime channel for a discharge of 64 cumecs as per Lacey's theory will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
According to Lacey's theory, following formulae has been given below:
- Hydraulic mean depth, \(R = \frac{5}{2}\frac{{{V^2}}}{f}\)
- Area of the channel section, \(A = \frac{Q}{V}\)
- Wetted perimeter, \(P = 4.75\sqrt Q \)
- Regime mean velocity, \(V = {\left( {\frac{{Q{f^2}}}{{140}}} \right)^{1/6}}\)
- Bed Slope, \(S = \frac{{{f^{5/3}}}}{{3340{Q^{1/6}}}}\)
Calculation:
\(P = 4.75\sqrt Q =4.75\sqrt 64 = 38 \;m\)
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