Using cos(A + B) = cos A cos B - sin A sin B, find the value of cos75°. 

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SSC CGL 2023 Tier-I Official Paper (Held On: 17 Jul 2023 Shift 3)
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  1. \(\frac{\sqrt5-1}{4}\)
  2. \(\frac{\sqrt5+1}{4}\)
  3. \(\frac{\sqrt6-\sqrt2}{4}\)
  4. \(\frac{\sqrt6+\sqrt2}{4}\)

Answer (Detailed Solution Below)

Option 3 : \(\frac{\sqrt6-\sqrt2}{4}\)
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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Formula used:

cos(A + B) = cos A cos B - sin A sin B. 

Calculation:

Cos 75° = cos (45° + 30°)

⇒ cos 45° × cos 30° - sin 45° × sin 30°

⇒ (1/√2)  × (√3/2)  - (1/√2)  × (1/2)

⇒ (√3/2√2) - (1/2√2)

⇒ (√3 - 1)/2√2

⇒ √2 × (√3 - 1)/(2√2 × √2)

⇒ \(\frac{\sqrt6-\sqrt2}{4}\)

∴ The correct answer is \(\frac{\sqrt6-\sqrt2}{4}\).

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