Question
Download Solution PDFTwo identical coils A and B have 400 turns placed such that 60% of flux produced by one coil links with the other. If a current of 10A flowing in coil A produces a flux of 20 mWb in it, find the mutual inductance between coil A and B.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The value of the mutual inductance is given by:
\(M={N_B\space × \spaceϕ_{BA}\over {I_A}}\)
where, M = Mutual inductance
Calculation
Given, NB = 400
IA = 10 A
ϕA = 20 mWb
60% of the flux produced by coil A links with coil B.
ϕBA = 0.6 × ϕA
ϕBA = 0.6 × 20 mWb = 12 mWb
\(M={400\space × 12\times 10^{-3}\over 10}=0.48H\)
Last updated on May 29, 2025
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