Question
Download Solution PDFThe value of a series resistor required to limit the current through an electric bulb to 40 mA with a forward voltage drop of 4V when connected to 16 V supply is ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The voltage drop across the series resistor (VR) is the difference between the supply voltage and the forward voltage drop of the bulb.
\(V_R=V_T-V_{Bulb}\)
Then, the value of a series resistor is given by:
\(I={V_R\over R}\)
Calculation:
Given, VT = 16V
VBulb = 4V
I = 40 mA = 0.04 A
\(V_R=16-4=12V\)
\(R={12\over 0.04}=300\space \Omega\)
Last updated on Jun 16, 2025
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