The total current flowing through a parallel connection of 20 Ω and 60 Ω resistors is 40 A. What will be the current flowing through the 60 Ω resistor?

Concept: 

Current division rule:

When 'n' resistors are connected in parallel across a current source, then-current is divided as follows

\({I_{R1}} = I\left[ {\frac{{{\frac1{R_1} }}}{{\frac1{R_1} + \frac1{R_2}+ ~......~+\frac1{R_n}}}} \right]\)

When two resistors are connected in parallel, then-current is divided as follows

By using current division rule,

The current flows through the resistor R1 is \({I_{R1}} = I\left( {\frac{{{R_2}}}{{{R_1} + {R_2}}}} \right)\)

The current flows through the resistor R2 is \({I_{R2}} = I\left( {\frac{{{R_1}}}{{{R_1} + {R_2}}}} \right)\)

Application;

Let R₁ = 20 Ω, R₂ = 60 Ω, I = 40 A

\({I_{R2}} = I\left( {\frac{{{R_1}}}{{{R_1} + {R_2}}}} \right)\)

I_R2 = I_60Ω = 40 × (20 / 80) 

I_60Ω = 10 A