The pressure in meters of oil (of specific gravity 0.8), equivalent to 80 m of water is:

Question

Question

This question was previously asked in

OSSC JE Civil Mains Official Paper: (Held On: 16th July 2023)

Answer 1

Concept:

We know that; P = ρgh

In terms of specific gravity, P = h × G

Notice that all the options are given in terms of the water column hence we will calculate on the basis of properties of water.

When Pressure is equivalent for two different liquids,

hoil × Goil = hwater × Gwater

Calculation:

Given:

Goil = 0.8

hwater = 80 m

Gwater = 1

hoil × Goil = hwater × Gwater

\({h_{oil}} = \frac{{{h_w}}}{{{G_{oil}}}} = \frac{{80}}{{0.8}} = 100\ m\)