Question
Download Solution PDFThe vertical component of pressure force on a submerged curved surface is equal to
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The hydrostatic force on the curved surface on horizontal direction:
\(F_H=ρ g {\bar h}A\)
where
\(ρ=\) the density of the fluid
g = acceleration due to gravity
\(\bar h=\) the distance of the center of gravity of the body from the free surface level
A = vertical projection of the area
The hydrostatic force on the curved surface on vertical direction:
V = volume of the above-curved surface up to the free surface level
Note:
The vertical component of hydrostatic force on a submerged curved surface is equal to the weight of the liquid above-curved surface up to the free surface level (ρgV).
Important Points
Hydrostatic force on a plane's submerged surface is given by
F = Pressure at the centroid × Area of the surface acts on the center of pressure
F = ρgh̅A
For a plane surface of arbitrary shape immersed in a liquid in such a way that the plane of the surface makes an angle θ with the free surface of the liquid:
Center of pressure, \({h^*} = \frac{{{I_G}{{\sin }^2}\theta }}{{A̅ h}} + \bar h\)
A = Total area of an inclined surface
h̅ = Depth of center of gravity of inclined area from a free surface
h* = Distance of center of pressure from the free surface of a liquid
Last updated on Jun 4, 2025
-> OSSC JE Preliminary Fiinal Answer Key 2025 has been released. Applicants can raise objections in OSSC JE answer key till 06 June 2025.
-> OSSC JE prelim Exam 2025 was held on 18th May 2025.(Advt. No. 1233/OSSC ).
-> The OSSC JE 2024 Notification was released for 759 vacancies through OSSC CTSRE 2024.
-> The selection is based on the written test. This is an excellent opportunity for candidates who want to get a job in the Engineering sector in the state of Odisha.
-> Candidates must refer to the OSSC JE Previous Year Papers to understand the type of questions in the examination.