The power dissipated in the 6Ω resistor is _______.

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SSC JE Electrical 06 Jun 2024 Shift 2 Official Paper - 1
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  1. 1000 W
  2. 1024 W
  3. 1536 W
  4. 3456 W

Answer (Detailed Solution Below)

Option 3 : 1536 W
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Detailed Solution

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Concept

The power dissipated by a resistor is:

\(P={I^2\times R}\)

where, P = Power

I = Current 

R = Resistance

Calculation

The current across 6Ω resistance is given by:

\(I=40\times{4\over 4+6}=16A\)

\(P={(16)^2\times 6}\)

P = 1536 W

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