Question
Download Solution PDFThe power dissipated in the 6Ω resistor is _______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The power dissipated by a resistor is:
\(P={I^2\times R}\)
where, P = Power
I = Current
R = Resistance
Calculation
The current across 6Ω resistance is given by:
\(I=40\times{4\over 4+6}=16A\)
\(P={(16)^2\times 6}\)
P = 1536 W
Last updated on Jun 16, 2025
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