Question
Download Solution PDFThe ordinate and abscissa of the diagram to depict the isobaric processes of an ideal gas as a hyperbola are, respectively
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The ideal gas equation is given by
PV = mRT
P = ρRT
For isobaric process
P1 = P2
∴ ρT = Constant, which is the equation for rectangular hyperbola.
Last updated on Jun 23, 2025
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