The molecular ion peak [M].+ of an analyte as measured by Electron Ionization Mass Spectrometry has an m/z of 149 and a relative abundance of 100%. The [M].+ has a relative abundance of 6.7% and the [M + 2].+peak has a relative abundance of 5%. The abundance of the major isotope of H, C, N, O, and S are 1H-100%, 12C-98.9%, 13C-1.1% , 14N-99.6%, 15N-0.4%, 16O, 99.8%, 18O-0.2%, 32S-95.0%, 33S-0.75% and 34S-4.2%. The most probable molecular formula of the compound is:

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CSIR-UGC (NET) Life Science: Held on (17 Feb 2022 Shift 1)
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  1. C7H21N2O
  2. C5H11NO2S
  3. C6H13O2S
  4. C6H15NOS

Answer (Detailed Solution Below)

Option 2 : C5H11NO2S
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Detailed Solution

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Concept:

  • ​In the process of ionizing solid or gas phase atoms or molecules, energetic electrons contact with them to produce ions.
  • This process is known as electron ionization (EI, formerly known as electron impact ionization and electron bombardment ionization).
  • One of the first mass spectrometry ionization methods created was EI.
  • The charge number is the quantity of electrons eliminated (for positive ions).
  • The horizontal axis in a mass spectrum is stated in units of mass divided by charge number, or m/z.

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Conclusion:-

So, The most probable molecular formula of the compound is C5H11NO2S

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