Question
Download Solution PDFThe Euler’s load (p) equal to \(\rm \frac{\pi^2 EI}{4L^2}\) is applicable for a long column with the end condition as:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
The maximum load at which the column tends to have lateral displacement or tends to buckle is known as buckling or crippling load. Load columns can be analyzed with the Euler’s column formulas can be given as:
\(P = \frac{{{n^2}{\pi ^2}EI}}{{{L^2}}}\)
- For both end hinged, n = 1
- For one end fixed and other free, n = 1/2
\(P = \frac{{{\pi ^2}EI}}{{4{L^2}}}\)
- For both end fixed, n = 2
- For one end fixed and other hinged, n = √2
Last updated on Mar 26, 2025
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