The current ratio \(\left(\frac{i_2}{i} \right) \) for the circuit shown in fig. is:

F1 Vinanti Engineering 09.02.23 D11

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  1. \(\frac{-L_2}{(L_1+L_2)} \)
  2. \(\frac{L_1}{(L_1+L_2)} \)
  3. \(\frac{L_2}{(L_1+L_2)} \)
  4. \(\frac{-L_1}{(L_1+L_2)} \)

Answer (Detailed Solution Below)

Option 2 : \(\frac{L_1}{(L_1+L_2)} \)
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Detailed Solution

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Applying the current divider rule :

 ⇒i2 = \(i\times\frac{L_1}{(L_1+L_2)} \)

\(\left(\frac{i_2}{i} \right) =\frac{L_1}{(L_1+L_2)}\)

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