The base of a pyramid is a square of side 10 cm. If its height is 10 cm, then the area (in cm2) of its lateral suface is:

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SSC CGL Tier 2 Quant Previous Paper 1 (Held On: 15 November 2020)
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  1. 50√5
  2. 100√5
  3. 100
  4. 100(√5 + 1)

Answer (Detailed Solution Below)

Option 2 : 100√5
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Detailed Solution

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Given:

The base of the pyramid is a square 

Side of square = 10 cm 

Height of pyramid = 10 cm 

Concept used:

Lateral surface = (1/2) × Perimeter of the base × Slant height

Calculations:

F1 Vaibhav 14.12.20 Pallavi D1

Slant height = EF 

Height = EO = 10 cm

OF = 10/2 = 5 cm

In ΔEOF,

EF2 = OE2 + OF2

⇒ 102 + 52 

⇒ EF = √125 = 5√5 

Slant height = EF = 5√5 cm

Perimeter of the base = 4 × 10 = 40 cm

Lateral surface = (1/2) × Perimeter of the base × Slant height

⇒ (1/2) × 40 × 5√5 

⇒ 100√5 cm

∴ The lateral surface are of the pyramid is 100√5 cm2

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