Solid Figures MCQ Quiz - Objective Question with Answer for Solid Figures - Download Free PDF

Last updated on Jun 15, 2025

Visualising Solid Shapes Question Answers with detailed solutions is now possible for all those who attempt this practice set. Access this online Solid Shapes MCQ Quiz test for all chapters and important concepts from the topic. Solve all the questions with accuracy and perfect the Solid Shapes Objective Questions by the end. This is an important topic for the candidates who want to ace the interviews, competitive exams and entrance exams. Start practising today.

Latest Solid Figures MCQ Objective Questions

Solid Figures Question 1:

A rectangular sheet of 31.4 cm x 10 cm size is rolled across its length to make a cylinder without overlap. What will be the approximate volume of the cylinder?

  1. 785 cm³
  2. 1570 cm³
  3. 3140 cm³
  4. 6280 cm³

Answer (Detailed Solution Below)

Option 1 : 785 cm³

Solid Figures Question 1 Detailed Solution

Given:

Length of rectangular sheet = 31.4 cm

Breadth of rectangular sheet = 10 cm

Formula used:

Circumference of the base of the cylinder = Length of the sheet

Height of the cylinder = Breadth of the sheet

Volume of the cylinder = π × r2 × h

Where, r = radius of the base, h = height

Calculation:

Length of the sheet = Circumference of the base = 2πr

⇒ 31.4 = 2 × 3.14 × r

⇒ r = 31.4 / (2 × 3.14)

⇒ r = 5 cm

Height of the cylinder = Breadth of the sheet = 10 cm

Volume of the cylinder = π × r2 × h

⇒ Volume = 3.14 × (5)2 × 10

⇒ Volume = 3.14 × 25 × 10

⇒ Volume = 785 cm3

∴ The correct answer is option (1).

Solid Figures Question 2:

The combined perimeter of the top and bottom circular faces of a right circular cylinder is 176 cm. The volume of the cylinder is given as 3528π cm³. If the height of the cylinder is three-fourths the length of a side of a square, what is the area of the square (in cm²)?

  1. 400
  2. 784
  3. 476
  4. 576
  5. 625

Answer (Detailed Solution Below)

Option 4 : 576

Solid Figures Question 2 Detailed Solution

Calculation

ATQ, 2 ×(2πr) = 176

Or, 2πr = 88

Or, πr = 44

So, r = 14 cm

Volume of the cylinder = [22/7] r2h = 3528π

So, 196h = 3528

So, h = 18

Side of the square = 18 × [4 / 3] = 24 cm

Required area = 24 × 24 = 576 cm

Solid Figures Question 3:

If the diameter of a sphere is increased by 30%, then increase in the surface area is 

  1.  69%
  2. 81%
  3. 27%
  4. 169%

Answer (Detailed Solution Below)

Option 1 :  69%

Solid Figures Question 3 Detailed Solution

Given:

The diameter of a sphere is increased by 30%.

Formula used:

Surface area of a sphere = 4πr2

Where r is the radius of the sphere.

Calculations:

Let the original diameter of the sphere be D, and the original radius be r = D/2.

So, the original surface area = 4πr2.

Now, if the diameter is increased by 30%, the new diameter is:

New diameter = D × (1 + 30/100) = 1.30D

The new radius is:

New radius = 1.30 × r = 1.30r.

The new surface area is:

New surface area = 4π(1.30r)2 = 4π × 1.69r2 = 1.69 × (4πr2).

The increase in the surface area is:

Increase = 1.69 × (original surface area) - original surface area

⇒ Increase = (1.69 - 1) × (original surface area)

⇒ Increase = 0.69 × (original surface area).

∴ The increase in the surface area is 69%.

Solid Figures Question 4:

A 5 m wide cloth is used to make a conical tent of base diameter 14 m and height 24 m. Find the cost of cloth used at the rate of Rs. 25 per metre square. [Use π = 22/7]

  1. Rs. 23750
  2. Rs. 13750
  3. Rs. 14750
  4. Rs. 13650
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : Rs. 13750

Solid Figures Question 4 Detailed Solution

Given:

breadth = 5 m

diameter = 14 m

height = 24 m

Rate = Rs. 25/m

Formula used:

CSA(Cone) = 22/7 x r x l

l2 = h2 + r2 

r = radius of the cone/tent(here)

h = slant height

CSA = Curved Surface Area

Solution:

r = 14/2 = 7 m

l = \(\sqrt{24^2 + 7^2} = \sqrt{576 + 49} = \sqrt{625}\)

l = 25 m

CSA = 22/7 x 7 x 25 

CSA = 550 m2 

Cost of cloth required = 550 x 25 = Rs. 13750

Hence, the correct option is 2.

Solid Figures Question 5:

A large cube with a side length of 28 meters is melted to form n small cubes and 7 medium cubes. From another large cube of same size, 16 small cubes and m medium cubes are formed. In both cases, the dimensions of the small and medium cubes remain consistent. If the side length of a small cube is 7 meters and that of a medium cube is 14 meters, then what is the value of n + m?

  1. 11
  2. 14
  3. 15
  4. 10
  5. 16

Answer (Detailed Solution Below)

Option 2 : 14

Solid Figures Question 5 Detailed Solution

Calculation

Given:

Large cube side = 28 m

Small cube side = 7 m

Medium cube side = 14 m

First large cube gives: n small + 7 medium cubes

Second identical cube gives: 16 small + m medium cubes

We are to find n + m

Volume of large cube = 28= 28 × 28 × 28 = 21952 m3

Volume of small cube = 7= 343 m3

Volume of medium cube = 143 = 2744 m3

n × 343 + 7 × 2744 = 21952

× 343 + 19208 = 21952

× 343 = 2744

⇒n = 2744/343 = 8

16 × 343 + m × 2744 = 21952

⇒ 5488 + m × 2744 = 21952

⇒ × 2744 = 16464

⇒ m = 16464/2744 = 6

So, n + m = 8 + 6 = 14

The correct answer is Option (2).

Top Solid Figures MCQ Objective Questions

A solid hemisphere has radius 21 cm. It is melted to form a cylinder such that the ratio of its curved surface area to total surface area is 2 ∶ 5. What is the radius (in cm) of its base (take  π = \(\frac{{22}}{7}\))?

  1. 23
  2. 21
  3. 17
  4. 19

Answer (Detailed Solution Below)

Option 2 : 21

Solid Figures Question 6 Detailed Solution

Download Solution PDF

Given:

The radius of a solid hemisphere is 21 cm.

The ratio of the cylinder's curved surface area to its Total surface area is 2/5.

Formula used:

The curved surface area of the cylinder = 2πRh

The total surface area of cylinder = 2πR(R + h)

The volume of the cylinder = πR2h

The volume of the solid hemisphere = 2/3πr³ 

(where r is the radius of a solid hemisphere and R is the radius of a cylinder)

Calculations:

According to the question,

CSA/TSA = 2/5

⇒ [2πRh]/[2πR(R + h)] = 2/5

⇒ h/(R + h) = 2/5

⇒ 5h = 2R + 2h

⇒ h = (2/3)R .......(1)

The cylinder's volume and the volume of a solid hemisphere are equal.

⇒ πR2h = (2/3)πr3

⇒ R2 × (2/3)R = (2/3) × (21)3

⇒ R3 = (21)3

⇒ R = 21 cm

∴ The radius (in cm) of its base is 21 cm.

The surface area of three faces of a cuboid sharing a vertex are 20 m2, 32 m2 and 40 m2. What is the volume of the cuboid?

  1. 92 m3
  2. √3024 m3
  3. 160 m3
  4. 184 m3

Answer (Detailed Solution Below)

Option 3 : 160 m3

Solid Figures Question 7 Detailed Solution

Download Solution PDF

The surface area of three faces of a cuboid sharing a vertex are 20 m2, 32 m2 and 40 m2,

⇒ L × B = 20 sq. Mt

⇒ B × H = 32 sq. Mt

⇒ L × H = 40 sq. Mt

⇒ L × B × B × H × L × H = 20 × 32 × 40

⇒ L2B2H2 = 25600

⇒ LBH = 160

∴ Volume = LBH = 160 m3

A solid cube of side 8 cm is dropped into a rectangular container of length 16 cm, breadth 8 cm and height 15 cm which is partly filled with water. If the cube is completely submerged, then the rise of water level (in cm) is:

  1. 6
  2. 4
  3. 2
  4. 5

Answer (Detailed Solution Below)

Option 2 : 4

Solid Figures Question 8 Detailed Solution

Download Solution PDF

Given:

Each side of the cube = 8 cm

The rectangular container has a length of 16 cm, breadth of 8 cm, and height of 15 cm

Formula used:

The volume of cube = (Edge)3

The volume of a cuboid = Length × Breadth × Height

Calculation:

The volume of cube = The volume of the rectangular container with length of 16 cm, breadth of 8 cm, and height of the water level rise

Let, the height of the water level will rise = x cm

So, 83 = 16 × 8 × x

⇒ 512 = 128 × x

⇒ x = 512/128 = 4

∴ The rise of water level (in cm) is 4 cm

The sum of length, breadth and height of a cuboid is 21 cm and the length of its diagonal is 13 cm. Then the total surface area of the cuboid is 

  1. 272 cm2
  2. 240 cm2
  3. 314 cm2
  4. 366 cm2

Answer (Detailed Solution Below)

Option 1 : 272 cm2

Solid Figures Question 9 Detailed Solution

Download Solution PDF

Given:

Sum of length,, breadth and height of a cuboid = 21 cm

Length of the diagonal(d) = 13 cm

Formula used:

d2 = l2 + b2 + h2

T.S.A of cuboid = 2(lb + hb +lh)

Calculation:

⇒ l2 + b2 + h2 = 132 = 169

According to question,

⇒ (l + b + h)2 = 441

⇒ l2 + b2 + h2 + 2(lb + hb +lh) = 441

⇒ 2(lb + hb +lh) = 441 - 169 = 272

∴ The answer is 272 cm2 .

Three cubes with sides in the ratio of 3 ∶ 4 ∶  5 are melted to form a single cube whose diagonal is 18√3 cm. The sides of the three cubes are:

  1. 21 cm, 28 cm and 35 cm
  2. 9 cm, 12 cm and 15 cm
  3. 18 cm, 24 cm and 30 cm
  4. 12 cm, 16 cm and 20 cm

Answer (Detailed Solution Below)

Option 2 : 9 cm, 12 cm and 15 cm

Solid Figures Question 10 Detailed Solution

Download Solution PDF

Given:

Three cubes with sides in the ratio of 3 ∶ 4 ∶  5 are melted to form a single cube whose diagonal is 18√3 cm.

Concept used:

The diagonal of a cube = √3a (where a is the sides)

Calculation: 

Let the s sides of the cubes will be 3x cm , 4x cm, and 5x cm

As per the question,

Volume of the new cube is 

(3x)3 +( 4x)3 +( 5x)3 = 216 x3.

⇒ side is = 6x

diagonal is 6x√3

⇒  6x√3 = 18√3

⇒ x = 3

The sides of the cubes will be 9 cm , 12 cm, and 15 cm

∴ The correct option is 2

 If the surface area of a sphere is 1386 cm2, then find the radius of the sphere.

  1. 12.5 cm
  2. 10.5 cm
  3. 10 cm
  4. 12 cm

Answer (Detailed Solution Below)

Option 2 : 10.5 cm

Solid Figures Question 11 Detailed Solution

Download Solution PDF

GIVEN:

The surface area of a sphere = 1386 \(cm^2\) 

FORMULA USED:

The surface area of a sphere = 4πr2where r is the radius of the sphere.

CALCULATION:

The surface area of a sphere =4πr2 = 1386 

⇒  4 × (22/7) × r2 = 1386      ....(value of  \(\pi\) is \(\frac{22}{7}\))

⇒ r2 = 110.25 

⇒ r2 = \(\frac{11025}{100}\)  

⇒ r = \(\sqrt\frac{11025}{100}\) = \(\frac{105}{10}\) = 10.5 cm.

∴ The radius of the sphere is 10.5 cm.

A solid cone with curved surface area twice its base area has slant height of 6√3 cm. Its height is:

  1. 6√2 cm
  2. 9 cm
  3. 6 cm
  4. 3√6 cm

Answer (Detailed Solution Below)

Option 2 : 9 cm

Solid Figures Question 12 Detailed Solution

Download Solution PDF

Given:

The curved surface area of the cone = 2 × base area of cone

Concepts used:

quesImage5679

Formula used

Slant height (l) of cone = √r2 + h2

CSA of cone = πrl

Calculation:

Let the radius of the cone be r units.

πrl = 2πr2

⇒ l = 2r

⇒ r = 6√3/2

⇒ r = 3√3

Slant height (l) of cone = √r2 + h2

⇒ 6√32 = 3√3+ h2

⇒ h2 = 108 - 27 = 81

⇒ h = 9 cm

∴ The answer is 9 cm.

To pack a set of books, Gautam got cartons of a certain height that were 48 inches long and 27 inches wide. If the volume of such a carton was 22.5 cubic feet, what was the height of each carton? [Use 1 foot = 12 inches.] 

  1. 36 inches
  2. 32.5 inches
  3. 30 inches
  4. 32 inches

Answer (Detailed Solution Below)

Option 3 : 30 inches

Solid Figures Question 13 Detailed Solution

Download Solution PDF

GIVEN:

Cartons having length = 48 inches and breadth = 27 inches 

The volume of cartoon = 22.5 cubic feet.

FORMULA USED :

Volume of Cuboid = Length × Breadth × Height 

CALCULATION :

Volume of carton = volume of cuboid = Length × Breadth × Height 

⇒ volume of carton = 48 × 27 × Height

∵ 1 foot = 12 inches, then 22.5 cubic feet = 22.5 × 12 × 12 ×12

⇒ 22.5 × 12 × 12 × 12 = 48 × 27 × Height     

⇒ 38,880 = 1,296 × Height 

⇒ Height = 30 inches.

∴ The height of each cartoon is 30 inches.                                     

A sphere of radius 42 cm is melted and recast into a cylindrical wire of radius 21 cm. Find the length of the wire.

  1. 224 cm
  2. 320 cm
  3. 322 cm
  4. 280 cm

Answer (Detailed Solution Below)

Option 1 : 224 cm

Solid Figures Question 14 Detailed Solution

Download Solution PDF

Given:

Radius of Sphere = 42 cm

Radius of wire = 21 cm

Formula:

Volume of cylinder = πr2h

Volume of sphere = [4/3]πr3

Calculation:

Let length of the wire be x, then

According to the question

π × 21 × 21 × x = [4/3] × π × 42 × 42 × 42 [As volume will remain constant]

⇒ x = (4 × 42 × 42 × 42)/(21 × 21 × 3)

⇒ x = 224 cm 

∴ The length of the wire is 224 cm

A spherical metal of radius 10 cm is molten and made into 1000 smaller spheres of equal sizes. In this process the surface area of the metal is increased by:

  1. 1000 times
  2. 100 times
  3. 9 times
  4. No change

Answer (Detailed Solution Below)

Option 3 : 9 times

Solid Figures Question 15 Detailed Solution

Download Solution PDF

Formula Used:

Volume of sphere = \(\frac{4}{3}\)πr3

Surface area of sphere = 4πr2

Calculation:

If the radius of a smaller sphere be 'r cm' then

Acoording to the question:

\(\frac{4}{3}\)π(10)3 = 1000\(\frac{4}{3}\)π(r)3

r = 1 cm

Surface area of the larger sphere = 4π(10)2 = 400π

Total surface area of 1000 smaller spheres = 1000 × 4π(1)2 = 4000π

Net increase in the surface area = 4000π − 400π = 3600π

Hence, surface area of the metal is increased by 9 times.

Get Free Access Now
Hot Links: teen patti gold apk teen patti gold lotus teen patti teen patti gold downloadable content