5x3 + 5x2 – 6x + 9ను (x + 3)చే భాగించగా వచ్చే శేషం

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CDS Maths Previous Paper 4 (Held On: 19 Nov 2017)
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  1. 135
  2. -135
  3. -63
  4. 63

Answer (Detailed Solution Below)

Option 3 : -63
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Detailed Solution

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ఉపయోగించిన భావన:

శేష సిద్ధాంతం:

బహుపది p(x)ని (x−a)తో భాగిస్తే, శేషం a

స్థిరాంకం p(a) ద్వారా ఇవ్వబడింది.

లెక్కింపు:

p(x) = 5x3 + 5x2 – 6x + 9 

(x + 3) p(x)ని భాగించబడనందున, శేషం p(-3) అవుతుంది.

⇒ p(-3) = 5 × (-3)3 + 5 × (-3)2 – 6 × (-3) + 9

⇒ p(-3) = -63

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