Question
Download Solution PDFजर 5x3 + 5x2 – 6x + 9 ला (x + 3) ने भागले असेल, तर बाकी किती?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवापरलेली संकल्पना:
बाकी प्रमेय:
जेव्हा बहुपदी P(x) ला (x + a) ने भागले जाते, तेव्हा बाकी P(a) द्वारे दिले जाते.
गणना:
समजा p(x) = 5x3 + 5x2 – 6x + 9
ज्याअर्थी p(x) ला (x + 3) ने भागले जाते, बाकी p(-3) असेल.
⇒ p(-3) = 5 × (-3)3 + 5 × (-3)2 – 6 × (-3) + 9
⇒ p(-3) = -63
Last updated on May 29, 2025
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