Question
Download Solution PDF12 సెం.మీ ఎత్తు మరియు 6 సెం.మీ వ్యాసం కలిగిన ఘన లోహస్థూపాన్ని కరిగించడం ద్వారా 6 సెం.మీ. వ్యాసంతో తయారు చేయగల ఘన గోళాల సంఖ్యను కనుగొనండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చిన సమస్య
స్థూపం కొలతలు: ఎత్తు = 12 సెం.మీ., వ్యాసం = 6 సెం.మీ
గోళ వ్యాసం: 6 సెం.మీ
పద్దతి: ఘనపరిమాణం లెక్కింపు మరియు పోలిక.
సాధన:
స్థూపం ఘనపరిమాణం = πr2h = π3212 = 108π సెం.మీ3
గోళ పరిమాణం = 4/3πr3 = 4/3π33 = 36π సెం.మీ3
గోళాల సంఖ్య = స్థూపం ఘనపరిమాణం/గోళం ఘనపరిమాణం
108π/36π = 3
అందువల్ల, 3 ఘన గోళాలను తయారు చేయవచ్చు.
Last updated on Jun 12, 2025
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