\(x+\frac{1}{x}=7\) எனில், \(x^3+\frac{1}{x^3}\) இன் மதிப்பைக்  காண்க.

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SSC Selection Post 2024 (Higher Secondary Level) Official Paper (Held On: 25 Jun, 2024 Shift 4)
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  1. 343
  2. 332
  3. 340
  4. 322

Answer (Detailed Solution Below)

Option 4 : 322
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கொடுக்கப்பட்டது:

\(x+\frac{1}{x}=7\) எனில், \(x^3+\frac{1}{x^3}\) இன் மதிப்பைக் கண்டுபிடி.

பயன்படுத்தப்படும் சூத்திரம்:

\((x + \frac{1}{x})^3 = x^3 + \frac{1}{x^3} + 3(x + \frac{1}{x})\)

கணக்கீடு:

\(x+\frac{1}{x}=7\)

\( (x+\frac{1}{x})^3 = 7^3 \)

\( x^3 + \frac{1}{x^3} + 3(x+\frac{1}{x}) = 343 \)

\( x^3 + \frac{1}{x^3} + 3 \times 7 = 343 \)

\( x^3 + \frac{1}{x^3} + 21 = 343 \)

\( x^3 + \frac{1}{x^3} = 343 - 21 \)

\( x^3 + \frac{1}{x^3} = 322 \)

∴ சரியான விடை விருப்பம் (4).

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