\(\rm \sqrt{\frac{1+sinA}{1-sinA}} =\)  ________.

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SSC CGL 2022 Tier-I Official Paper (Held On : 05 Dec 2022 Shift 4)
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  1. coescA - cotA 
  2. secA - tanA 
  3. secA + tanA 
  4. secA

Answer (Detailed Solution Below)

Option 3 : secA + tanA 
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Detailed Solution

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Given:

\(\rm \sqrt{\frac{1+sinA}{1-sinA}} \)

Concept Used:

The concept of conjugation is used here

Calculation:

⇒ \(\rm \sqrt{\frac{1+sinA}{1-sinA}} \)

Now, Conjugate the above equations

⇒ \(\rm {\sqrt{\frac{1+sinA}{1-sinA} \times \rm {\frac{1+sinA}{1+sinA}}}}\)

⇒ \(\rm \sqrt{\frac{(1+sinA)^2}{1-sin^2A}}\)

⇒ \(\rm \sqrt{\frac{(1+sinA)^2}{cos^2A}}\)

⇒ \(\rm {\frac{(1+sinA)}{cosA}}\)

⇒ \(\frac{1}{ cos A} +\frac{sin A}{ cosA}\)

⇒ sec A + tan A 

⇒ Hence, Value of the given part is sec A + tan A

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