Question
Download Solution PDFRamu mixes 2 litres of water at 100° C and 18 litres of water at 32° C. What temperature will the water have after mixing?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Water quantities and temperatures:
- Water 1: 2 litres at 100°C
- Water 2: 18 litres at 32°C
Formula used:
Final temperature (T) after mixing = (m1 × T1 + m2 × T2) / (m1 + m2)
Where m1 and m2 are the masses (or volumes in this case, since the density of water is uniform), and T1 and T2 are the temperatures of the water.
Calculation:
⇒ T = (2 × 100 + 18 × 32) / (2 + 18)
⇒ T = (200 + 576) / 20
⇒ T = 776 / 20
⇒ T = 38.8°C
∴ The final temperature of the water after mixing is 38.8°C.
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