Question
Download Solution PDF\(\rm \tan^{-1}\left[\cos\left(-{\pi\over2}\right)\right]\)चे मूळ मूल्य किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
cos (-θ) = cos θ
\(\cos\left({\pi\over2}\right) = 0\)
गणना:
x = \(\rm \tan^{-1}\left[\cos\left(-{\pi\over2}\right)\right]\)
x = \(\rm \tan^{-1}\left[\cos\left({\pi\over2}\right)\right]\)
x = \(\rm \tan^{-1}\left[0\right]\)
∵ मूळ मूल्य ∈ \(\left[-{\pi\over2},{\pi\over2}\right]\)असू शकते
∴ x = 0
Last updated on May 31, 2025
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