A, B आणि C ही मूलद्रव्ये डोबेरेनरचे त्रिक म्हणून आढळतात. जर A चे अणूवस्तुमान 40 आणि C चे अणूवस्तुमान 137 असेल, तर B चे अणूवस्तुमान किती असेल?

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RRB ALP Previous Paper 2 (Held On: 9 Aug 2018 Shift 2)
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  1. 35
  2. 120
  3. 88
  4. 74

Answer (Detailed Solution Below)

Option 3 : 88
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  • डोबेरेनरच्या त्रिकांचा नियमानुसार, त्रिकातील मध्य मूलद्रव्याचे अणुवस्तुमान इतर दोन मूलद्रव्याच्या अणुवस्तुमानचे गणितीय मध्य असतो.

  • जर A, B आणि C डोबेरेनरच्या त्रिकुटामधील मूलद्रव्य असतील तर B चा अणुवस्तुमान A आणि C च्या अणुवस्तुमानचे गणितीय मध्य समान असेल

 

 

मूलद्रव्य

A

C

B = (A + C)/2

आण्विक वस्तुमान

40

137

= (40 + 137) / 2 ≈ 88

अणु संख्या

20

56

38

मूलद्रव्य

कॅल्शियम

बेरियम

स्ट्रॉन्शियम

 

म्हणून मूलद्रव्य B चा अणुवस्तुमान 88 आहे.
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