Question
Download Solution PDFवर फेकलेला चेंडू 10 सेकंदानंतर जमिनीवर परत येतो. तो कोणत्या वेगाने वर फेकला गेला ते शोधा? (जर g = 10 मीटर/सेकंद2).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
We know that the time taken by the ball to reach the maximum height is half of the total time taken to return to the ground. So, the ball reached the maximum height after 5 seconds.
So, using the formula of the equation of motion for velocity i.e.
v = u + at
since at the maximum height, the velocity of the ball would be zero.
So, v = 0
0 = u -10×5
u = 50 m/s
The correct answer is option "2"
Last updated on Jun 26, 2025
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