Maximum value of shear stress for a hollow shaft of outer and inner diameter D and d will be: [where T = Applied torque]

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  1. \(\frac{16TD}{\pi(D^3 - d^3)}\)
  2. \(\frac{16TD}{\pi(D^4 - d^4)}\)
  3. \(\frac{16T}{\pi(D^4 - d^4)}\)
  4. \(\frac{16T}{\pi(D^3 - d^3)}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{16TD}{\pi(D^4 - d^4)}\)
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Detailed Solution

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Concept:

Considering the rigidity of shaft,

The maximum shear stress induced in the solid shaft of diameter d, to transmit twisting moment T is given by,

\(\tau_{max}\;=\frac{{16T}}{{\pi d^3 }}\)

The maximum shear stress induced in the hollow shaft of outer diametr do and inner diameter di to transmit the twisting moment T.

.\(\tau_{max}\;=\frac{{16T}}{{\pi d_o^3 (1-K^4)}}\), where K is the ratio of outer and inner diameter, \(K =\frac{{d_i}}{{d_o}}\)

Explanation:

Given:

do = D, di = d

⇒ τmax = \(\frac{16TD}{\pi(D^4 - d^4)}\)

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