In the standard Ethernet with transmission rate of 10Mbps, assume that the length of the medium is 2500m and size of a frame is 512 bytes. The propagation speed of a signal in a cable is normally 2 × 108 m/s. Calculate Transmission delay and propagation delay.

This question was previously asked in
UGC NET Computer Science (Paper 2) 11 March 2023 Official Paper
View all UGC NET Papers >
  1. 25.25μs and 51.2μ
  2. 51.2μs and 12.5μs 
  3. 10.24μs and 50.12μs
  4. 12.5μs and 51.2μs

Answer (Detailed Solution Below)

Option 2 : 51.2μs and 12.5μs 
Free
UGC NET Paper 1: Held on 21st August 2024 Shift 1
10.8 K Users
50 Questions 100 Marks 60 Mins

Detailed Solution

Download Solution PDF

The correct answer is 51.2μs and 12.5μs 

Key PointsThe delay in Ethernet transmission, which is measured by the duration required to send a single frame over the physical medium, is determined by dividing the frame size by the speed of transmission. In this case, the transmission delay is:
           Transmission delay = Frame size / Transmission rate
                  => 512 bytes / 10 Mbps = 51.2 microseconds

In Ethernet, the propagation delay denotes the time duration for a single bit to traverse from source to destination over the physical network medium. It's assessed by dividing the medium's length by the transmission speed of the signal. In this case, the propagation delay is:
          Propagation delay = Length of medium / Propagation speed
                  => 2500 m/2 x 10^8 m/s 12.5 microseconds

Consequently, in a standard Ethernet setup featuring a transmission rate of 10 Mbps, a medium length of 2500 m, and a frame size of 512 bytes, the correspondingly calculated transmission delay and propagation delay are 51.2μs and 12.5μs, respectively.

Latest UGC NET Updates

Last updated on Jun 6, 2025

-> The UGC NET Exam Schedule 2025 for June has been released on its official website.

-> The UGC NET Application Correction Window 2025 is available from 14th May to 15th May 2025.

-> The UGC NET 2025 online application form submission closed on 12th May 2025.

-> The June 2025 Exam will be conducted from 21st June to 30th June 2025

-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.

-> The exam is conducted bi-annually - in June and December cycles.

-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions. 

-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.

More Concept of Layering Questions

Get Free Access Now
Hot Links: teen patti gold downloadable content teen patti diya online teen patti teen patti gold apk download