Question
Download Solution PDFIn CRC coding if the data word is 111111, divisor is 1010 and the remainder is 110. Which of the following code is true?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is 111111110
Key PointsCyclic Redundancy Check (CRC) coding involves dividing a data word by a fixed divisor to generate a remainder, which is then appended to the original data word to form the transmitted message.
In this case, the given data word is 111111, the divisor is 1010, and the remainder is 110.
To find the transmitted message, you append the remainder to the original data word. So, the transmitted message is 111111110.
Therefore, the correct option is: 3) 111111110
Last updated on Jun 6, 2025
-> The UGC NET Exam Schedule 2025 for June has been released on its official website.
-> The UGC NET Application Correction Window 2025 is available from 14th May to 15th May 2025.
-> The UGC NET 2025 online application form submission closed on 12th May 2025.
-> The June 2025 Exam will be conducted from 21st June to 30th June 2025
-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.
-> The exam is conducted bi-annually - in June and December cycles.
-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions.
-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.