Question
Download Solution PDFIn the circuit shown, if we connect a source of 2 volt with internal resistance of 1 Ω at AA′ with positive terminal at A′, then the current through R is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
When source voltage is applied then
Applying source transformation in the current source
Applying Nodal Analysis
\(\rm \frac{V-1}{2}+\frac{V}{2}+\frac{V-2}{1}=0\)
or, \(\rm \frac{V-1+V+2V-4}{2}=0\)
or, 4 V = 5 ⇒ V = 1.25 V
∴ \(\rm I=\frac{1.25}{2}=0.625\ A\)
Therefore, the correct option is (4).
Last updated on Mar 26, 2025
-> UKPSC JE Notification for 2025 will be out soon!
-> The total number of vacancies along with application dates will be mentioned in the notification.
-> The exam will be conducted to recruit Junior Engineers through Uttarakhand Public Service Commission.
-> Candidates with an engineering diploma in the concerned field are eligible.
-> The selection process includes a written exam and document verification. Prepare for the exam with UKPSC JE Previous Year Papers.