Question
Download Solution PDFIn a 15 liter solution containing 40% acid and 60% water, 25 liter solution containing 60% acid and 40% water is added. Find the percentage of water in the resulting mixture.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
In a 15 litre solution 40% is acid and 60% is water and in 25 litre solution 60% is acid and 40% is water
Concept Used:
Concept of percentage.
The percentage is calculated based on 100
For example, 4 out of 10 means 40 out of 100 i.e. 40% of 10
Calculation:
In 15 litre solution, 40% is acid and 60% water.
That means, quantity of acid = (40/100) × 15
⇒ 6 litres
60% water that means (60/100) × 15
⇒ 9 litres
In 25 litre acid is 60% and water is 40%
That means, quantity of acid = (60/100) × 25
⇒ 15 litres
40% water means quantity of water = (40/100) × 25
⇒ 10 litre
From the above, acid in resultant mixture = (6 + 15) = 21 litters
Water in resultant mixture = (9 + 10) = 19 litters
Total resultant mixture = (15 + 25) = 40 litters
Percentage of water in resultant mixture = (19/40) × 100
⇒ 47.50%
∴ Percentage of water in resultant mixture is 47.50%
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