If x +\(\rm \frac{1}{x}\) = 1, then the value of \(\frac{x^2+7x+1}{x^2+11x+1}\) = ?

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SSC CGL 2023 Tier-I Official Paper (Held On: 26 Jul 2023 Shift 2)
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  1. \(\frac{3}{4}\)
  2. \(\frac{2}{3}\)
  3. \(\frac{1}{3}\)
  4. \(\frac{1}{4}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{2}{3}\)
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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Calculation:

x +\(\rm \frac{1}{x}\) = 1

⇒ x2 + 1 = x

By putting the value x2 + 1 = x we get,

\(\frac{x^2+7x+1}{x^2+11x+1}\) = \(x\space +\space 7x\over x\space +\space 11x\) 

⇒ 8x/12x = 2/3

∴ The correct option is 2

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