Question
Download Solution PDFIf the temperature of a black body doubles, how many times will its emissive power increase?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Black Body:
- A black body is an idealized physical object that absorbs all incident electromagnetic radiation, regardless of frequency or angle of incidence. A black body also emits radiation in a characteristic spectrum that depends only on its temperature, as described by Planck's Law.
Emissive Power:
- Emissive power of a black body refers to the total energy radiated per unit surface area per unit time. This is given by the Stefan-Boltzmann Law, which states:
E = σT4
Where:
- E = Emissive power (W/m2)
- σ = Stefan-Boltzmann constant (5.67 × 10-8 W/m2K4)
- T = Absolute temperature of the black body (in Kelvin)
Calculation:
If temperature doubles: T' = 2T
\( E' = \sigma (2T)^4 = 16 \cdot \sigma T^4 = 16E \)
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.