If the maximum demand is 100 kW, the load factor is 100%, then find Units generated/annum.

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SSC JE Electrical 14 Nov 2022 Shift 3 Official Paper
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  1. 876 TWh
  2. 876 Wh 
  3. 876 kWh
  4. 876 MWh

Answer (Detailed Solution Below)

Option 4 : 876 MWh
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Detailed Solution

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Load Factor

Load factor is defined as the ratio of the average load over a given period to the maximum demand (peak load) occurring in that period.

\(Load \space factor={Average \space demand \over Maximum \space demand}\)

The average demand is given by:

\(Average \space demand={Area \space under \space curve \over Total \space time(in\space hrs)}\)

The area under the curve gives the number of units generated/per annum.

Calculation

Given, Maximum demand = 100 kW

Load Factor = 100% = 1

\(1={Average \space demand \over 100}\)

Average demand = 100 kW

For 1 year = 8760 hrs

\(100× 10^3={Area \space under \space curve \over 8760}\)

No. of units generated = 876 × 106 Wh

No. of units generated = 876 MWh

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