If the average of s numbers is r4 and the average of r numbers is s4, the find the average of all r + s numbers? 

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SSC CGL 2022 Tier-I Official Paper (Held On : 09 Dec 2022 Shift 4)
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  1. rs \((r^2 + s^2 - rs) \)
  2. rs
  3. \(r^2 + s^2\)
  4. rs \((r^2 + s^2) \)

Answer (Detailed Solution Below)

Option 1 : rs \((r^2 + s^2 - rs) \)
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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Given:

The average of s numbers is r4 and the average of r numbers is s4.

Concept used:

1. a3 + b3 = (a + b)(a2 - ab + b2)

2. Total = Average × Number of entities

Calculation:

Total sum of s numbers = s × r4 = sr4

Total sum of r numbers = r × s4 = rs4

Now, the average of all r + s numbers

⇒ (rs4 + sr4) ÷ (r + s)

⇒ rs(s3 + r3) ÷ (r + s)

⇒ rs(s + r)(s2 - sr + r2) ÷ (r + s)

⇒ rs(s2 - sr + r2)

⇒ rs \((r^2 + s^2 - rs) \)

∴ The average of all r + s numbers is rs \((r^2 + s^2 - rs) \).

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