दी गई समीकरण को सही बनाने के लिए किन दो संख्याओं (व्यक्तिगत अंकों को नहीं) को आपस में बदलना होगा?

21 × 5 – 35 + (42 ÷ 7) + 28 = 96 

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SSC Selection Post 2024 (Matriculation Level) Official Paper (Held On: 26 Jun, 2024 Shift 1)
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  1. 28 और 35
  2. 35 और 42
  3. 21 और 42
  4. 28 और 21

Answer (Detailed Solution Below)

Option 2 : 35 और 42
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BODMAS

दिया गया है : 21 x 5 - 35 + (42 ÷ 7) + 28 = 96

प्रश्न के अनुसार, संख्याओं को बदलने के बाद :

विकल्प 1) 28 और 35

21 x 5 - 35 + (42 ÷ 7) + 28 = 96 21 x 5 - 28 + (42 ÷ 7) + 35 = 96

21 x 5 - 28 + (42 ÷ 7) + 35 = 96

21 x 5 - 28 + 6 + 35 = 96

105 + 6 + 35 - 28 = 96

146 - 28 = 96

⇒ 118 ≠ 96 (LHS RHS)

विकल्प 2) 35 और 42

21 x 5 - 35 + (42 ÷ 7) + 28 = 96 21 x 5 - 42 + (35 ÷ 7) + 28 = 96

21 x 5 - 42 + (35 ÷ 7) + 28 = 96

21 x 5 - 42 + 5 + 28 = 96

105 + 5 + 28 - 42 = 96

138 - 42 = 96

⇒ 96 = 96 (LHS = RHS)

विकल्प 3) 21 और 42

21 x 5 - 35 + (42 ÷ 7) + 28 = 96 42 x 5 - 35 + (21 ÷ 7) + 28 = 96

42 x 5 - 35 + (21 ÷ 7) + 28 = 96

42 x 5 - 35 + 3 + 28 = 96

210 + 3 + 28 - 35 = 96

241 - 35 = 96

⇒ 206 ≠ 96 (LHS RHS)

विकल्प 4) 28 और 21

21 x 5 - 35 + (42 ÷ 7) + 28 = 96 28 x 5 - 35 + (42 ÷ 7) + 21 = 96

28 x 5 - 35 + (42 ÷ 7) + 21 = 96

28 x 5 - 35 + 6 + 21 = 96

140 + 6 + 21 - 35 = 96

167 - 35 = 96

⇒ 132 ≠ 96 (LHS RHS)

इसलिए, "विकल्प 2" सही उत्तर है।

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