Question
Download Solution PDF4 पोल और 750 rpm घूर्णन वाले प्रत्यावर्तित्र द्वारा उत्पन्न वोल्टता की आवृत्ति कितनी है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही उत्तर विकल्प 2): 25 Hz है
संकल्पना:
एक प्रत्यावर्तित्र द्वारा उत्पन्न वोल्टेज की आवृत्ति इस प्रकार दी गयी है
\(f = \frac{{PN}}{{120}}\)
f = आवृत्ति (Hz में),
P = ध्रुवों की संख्या
N = गति (RPM में)
गणना:
दिया गया है
P = 4
N = 750 rpm
\(f = \frac{{4 \times 750}}{{120}} = 25\;Hz\)
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