एक समतल विद्युत चुम्बकीय तरंग में विद्युत क्षेत्र निम्न द्वारा दिया गया है:
Eₓ = 60 cos (5x + 1.5 x 10⁹ 𝜃) V/m.
तब संगत चुम्बकीय क्षेत्र के लिए व्यंजक होगा (यहाँ सबस्क्रिप्ट क्षेत्र की दिशा को दर्शाते हैं):

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NEET 2025 Official Paper (Held On: 04 May, 2025)
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  1. Bᵧ = 2 × 10⁻⁷ cos (5x + 1.5 × 10⁹𝜃) T
  2. Bₓ = 2 × 10⁻⁷ cos (5x + 1.5 × 10⁹𝜃) T
  3. B𝓏 = 60cos (5x + 1.5 × 10⁹𝜃) T
  4. B𝓏 = 60sin (5x + 1.5 × 10⁹𝜃) T

Answer (Detailed Solution Below)

Option 1 : Bᵧ = 2 × 10⁻⁷ cos (5x + 1.5 × 10⁹𝜃) T
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CT 1: Botany (Cell:The Unit of Life)
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Detailed Solution

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सही विकल्प: (1) By = 2 x 10⁻⁷ cos(5x + 1.5 x 10⁹t) T है। 

विद्युत चुम्बकीय तरंगों में, E और B समान कला में होते हैं और B0 = E0/c ; उनके तल एक दूसरे के लंबवत होते हैं।
By = (60 / c) cos(5x + 1.5 × 10⁹t) T
= (60 / 3 x 10⁸) cos(5x + 1.5 × 10⁹t) T
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