Question
Download Solution PDFA ball of mass 0.5 kg is dropped from a height of 40 m.The ball hits the ground and rises to a height of 10 m.The impulse imparted to the ball during its collision with the ground is (Take g = 9.8 m/s²)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCorrect option is: (1) 21 NS
v₁ = √(2gh₁)
= √(2 × 9.8 × 40)
= √784 = 28 m/s
v₂ = √(2gh₂) = √(2 × 9.8 × 10)
= √196 = 14 m/s
Impulse = Δp = m(vf − vi) = m(v₂ − (−v₁))
= (1/2)(14 − (−28))
Last updated on Jun 16, 2025
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