Question
Download Solution PDFनीचे दिये गये दो-पोर्ट समरूप नेटवर्क में पारेषण प्राचल 'A' है
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
संचरण मानदंड को निम्न द्वारा ज्ञात किया गया हैं:
V1 = AV2 - BI2
I1 = CV2 - DI2
\(A = ({V_1\over V_2})_{I_2=0}\)
गणना:
\(V_2 = {10 \over 30+10}V_1\)
\(A= {V_1 \over V_2}=4\)
Last updated on Jun 13, 2025
-> UPPSC AE Mains Exam 2025 registration has been started.
-> UPPSC AE Mains registration window is available till June 27. However, last date to send the documents is July 4.
-> UPPSC AE result 2025 has been released for Prelims exam.
-> UPPSC AE Answer Key 2025 has been uploaded on 23rd April 2025.
-> UPPSC AE Exam was conducted 20th April 2025 on its official website.
-> The UPPSC AE Exam Date 2025 has been released.
-> The Prelims & Mains exam will be conducted on 20th April & 28th September 2025 respectively.
-> A total of 604 vacancies have been released.
-> The applications must be submitted online between 17th December 2024 to 17th January 2025.
-> The selection process includes a written exam, interview, and document verification.
-> Candidates with a BE/B.Tech degree in the relevant discipline, between 21 to 40 years of age are eligible for this post.