मध्य मानों 30, 39, 48, 57 और 66 के लिए वितरण का द्वितीय वर्ग ________ है।

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SSC CGL Tier-II ( JSO ) 2017 Official Paper ( Held On : 22 Feb 2018 )
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  1. 34 - 44
  2. 34.5 - 43.5
  3. 33.5 - 44.5
  4. 34 - 45

Answer (Detailed Solution Below)

Option 2 : 34.5 - 43.5
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दिया गया है​:

मध्य मान = 30, 39, 48, 57, 66

प्रयुक्त सूत्र:

वर्ग अंतराल का मध्य मान = (L1 + L2)/2

L1 = निम्न सीमा

L2 = ऊपरी सीमा

गणना:

द्वितीय वर्ग के लिए मध्य मान (L1 + L2)/2 होगा 

यहाँ L1 और L2 वर्ग अंतराल के निम्न मान और ऊपरी मान हैं

  30 और 39 का मध्य बिंदु = (L1 + L2)/2

⇒ (30 + 39)/2 = 34.5

⇒ 39 और 48 का मध्य बिंदु

⇒ (39 + 48)/2 = 43.5

⇒ निम्न सीमा (L1 = 34.5)

⇒ ऊपरी सीमा (L2 = 43.5)

 इस वितरण का द्वितीय वर्ग 34.5 – 43.5 है।

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विकल्पों के अनुसार

1 – 34 – 44

वर्ग परिमाण 44 – 34 = 10

39 – 30  =9

अतः परिमाण अंतर मेल नहीं होता इसलिए विकल्प 1 गलत है

2 – 34.5 – 43.5

वर्ग परिमाण = 43.5 – 34.5 = 9

मध्य बिंदु अंतर

39 – 30 = 9, 48 – 39 = 9, 57 – 48 = 9, और 66 – 57 = 9

अतः विकल्प (2) वर्ग परिमाण के साथ सुमेलित है अतः विकल्प (2) सही है

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