Question
Download Solution PDFएक विद्युत बल्ब 200 V जनित्र से संबद्ध है। धारा 0.5 A है। बल्ब की सामर्थ्य क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा :
- विद्युत शक्ति : वह दर जिस पर विद्युत ऊर्जा ऊर्जा के अन्य रूपों में अपव्ययित होती है, विद्युत शक्ति कहलाती है अर्थात
\(P = \frac{W}{t} = VI = {I^2}R = \frac{{{V^2}}}{R}\)
जहां V = विभव अंतर, R = प्रतिरोध और I = धारा।
गणना:
दिए गए - विभव अंतर (V) = 200 V और धारा (I) = 0.5 A
- विद्युत शक्ति को निम्न रूप में लिखा जा सकता है,
⇒ P = VI
⇒ P = 200 × 0.5 = 100 W
Last updated on Jun 11, 2025
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