A plane wavefront of 7000 Å falls on an aperture. The area of half period zone of the diffraction pattern on screen 1 meter away from the aperture will be :

  1. 28 × 10-7 m2
  2. 44 × 10-7 m2
  3. 22 × 10-7 m2
  4. 14 x 10-7 m2

Answer (Detailed Solution Below)

Option 3 : 22 × 10-7 m2
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अवधारणा :

फ्रेस्नेल का अर्ध अवधि क्षेत्र (HPZ):

F1 Prabhu 27.11.20 Pallavi D4

  • फ्रेस्नेल के अनुसार पूरे तरंगाग्र को बड़ी संख्या में क्षेत्रों के हिस्सों में विभाजित किया जा सकता है जिन्हें फ्रेस्नेल के अर्ध-अवधि क्षेत्रों (HPZ) के रूप में जाना जाता है।
  • स्क्रीन पर किसी भी बिंदु पर परिणामी प्रभाव विभिन्न क्षेत्रों से सभी द्वितीयक तरंगों के संयुक्त प्रभाव के कारण होता है।

 

व्याख्या:

F1 Prabhu 27.11.20 Pallavi D5

  • अर्ध अवधि क्षेत्र की त्रिज्या है :

\(⇒ r_n=\sqrt{ndλ}\)

 

जहां n = क्षेत्रों की संख्या, बिंदु P से तरंगाग्र की दूरी, और λ = तरंग दैर्ध्य

  • The Area of the nth HPZ is given by 

An = πdλ 

Calculation:

Given d = 1m, λ = 7000 Å = 7 × 10-7 m;

Now the are of the HPZ will be 

A = π × 1 × 7 × 10-7 m2;

⇒ A = 21.99 × 10-7 m2;

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