Question
Download Solution PDFएक 3-फेज, 10 kV वितरण लाइन 0.8 पावर फैक्टर लैगिंग पर एक लोड को बिजली पहुँचाती है। यदि धारा 50 A है, और 400 मीटर लाइन के लिए प्रति किमी लोड प्रतिरोध और प्रतिघात क्रमशः 0.15 Ω और 0.2 Ω हैं, तो प्रति फेज में अनुमानित वोल्टेज ड्रॉप (V/फेज में) क्या है?
Answer (Detailed Solution Below)
Detailed Solution
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प्रति फेज वोल्टेज ड्रॉप (V/फेज में) दिया गया है:
V = I x ZT
जहाँ, V = वोल्टेज ड्रॉप
I = धारा
ZT = कुल प्रतिबाधा
गणना
दिया गया है, cosϕ = 0.8 lag → ϕ = 36.86°
I = 50∠-36.86°
लंबाई = 400 m = 0.4 km
ZT = (0.15 + j0.2) x 0.4
ZT = (0.06 + j0.08) Ω/km
V = (50∠-36.86°) x (0.06 + j0.08)
V = 50(0.8 - j0.6) x (0.06 + j0.08)
V = (40 - j30) x (0.06 + j0.08)
V = 4.8 + j1.4
Last updated on Jun 16, 2025
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