एक 3-फेज, 10 kV वितरण लाइन 0.8 पावर फैक्टर लैगिंग पर एक लोड को बिजली पहुँचाती है। यदि धारा 50 A है, और 400 मीटर लाइन के लिए प्रति किमी लोड प्रतिरोध और प्रतिघात क्रमशः 0.15 Ω और 0.2 Ω हैं, तो प्रति फेज में अनुमानित वोल्टेज ड्रॉप (V/फेज में) क्या है?

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RRB JE EE 22 Apr 2025 Shift 2 CBT 2 Official Paper
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  1. 0 + j10
  2. 1 + j10
  3. 4.8 + j1.4
  4. 1 + j5

Answer (Detailed Solution Below)

Option 3 : 4.8 + j1.4
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सिद्धांत

प्रति फेज वोल्टेज ड्रॉप (V/फेज में) दिया गया है:

V = I x ZT

जहाँ, V = वोल्टेज ड्रॉप

I = धारा

ZT = कुल प्रतिबाधा

गणना

दिया गया है, cosϕ = 0.8 lag → ϕ = 36.86°

I = 50∠-36.86°

लंबाई = 400 m = 0.4 km

ZT = (0.15 + j0.2) x 0.4

ZT = (0.06 + j0.08) Ω/km

V = (50∠-36.86°) x (0.06 + j0.08)

V = 50(0.8 - j0.6) x (0.06 + j0.08)

V = (40 - j30) x (0.06 + j0.08)

V = 4.8 + j1.4

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