Question
Download Solution PDFFor a parallel RLC resonant circuit with resistance in series with inductor, what will be the effect on resonant frequency, if we increase the value resistance?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
\({Y_{eq}} = \frac{1}{{R + j\omega L}} + j\omega C\)
\( = \frac{{R - j\omega L}}{{{R^2} + {\omega ^2}{L^2}}} + j\omega C\)
\(= \frac{R}{{{R^2} + {\omega ^2}{L^2}}} + \left[ {\omega C - \frac{{\omega L}}{{{R^2} + {\omega ^2}{L^2}}}} \right]\)
At resonant frequency, imaginary part of equivalent admittance is zero.
\(\Rightarrow \omega c = \frac{{\omega L}}{{R{\;^2} + {\omega ^2}{L^2}}}\)
\(\Rightarrow {R^2} + {\omega ^2}{L^2} = \frac{L}{C}\)
\(\Rightarrow {L^2}{\omega ^2} = \frac{L}{C} - {R^2}\)
\(\Rightarrow {\omega ^2} = \frac{1}{{LC}} - {\left( {\frac{R}{L}} \right)^2}\;\)
\(\omega = \sqrt {\frac{1}{{LC}} - {{\left( {\frac{R}{L}} \right)}^2}}\)
Application:
From the above expression, the resonant frequency decreases with an increase in resistance.
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