Find the voltage V0 across 4 Ω resistor in the following circuit.

F1 Koda Raju 12.4.21 Pallavi D5

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SSC JE EE Previous Paper 12 (Held on: 24 March 2021 Evening)
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  1. 20 V
  2. 12 V
  3. 24 V
  4. 18 V

Answer (Detailed Solution Below)

Option 3 : 24 V
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Detailed Solution

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Concept:

Kirchhoff’s Current Law:

It says the total current entering a circuits junction is exactly equal to the total current leaving the same junction.

Or sum of all current entering or leaving a node is zero

F6 U.B Madhu 03.03.20 D3

According to KCL: ∑I = 0

Applying KCL:

I1 + I2 – I3 – I4 – I5 = 0

I1 + I2 = I3 + I4 + I5

Calculation:

F1 Koda Raju 12.4.21 Pallavi D5

Apply KCL at node 'a'

i0 = 0.5i0 + 3

0.5i0 = 3

i0 = 6 A

∴v0 = 4i0 = 4× 6 = 24 V

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