Question
Download Solution PDFFind the electrical energy consumed in 10Ω resistance when 100 mA current flows for 2 minutes.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The energy consumed by electrical appliances is given by:
E = P × t
E = I2R × t
where, E = Energy
I = Current
R = Resistance
t = Time
Calculation
Given, I = 100 mA = 0.1 A
R = 10 Ω
t = 2 min = 120 sec
E = 0.12 × 10 × 120
E = 12 J
Last updated on Jul 1, 2025
-> SSC JE Electrical 2025 Notification is released on June 30 for the post of Junior Engineer Electrical, Civil & Mechanical.
-> There are a total 1340 No of vacancies have been announced. Categtory wise vacancy distribution will be announced later.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.