Compute the cartesian components of the electric field at the point if the potential at any point is given by V = x (y2 - 4x2)?

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AAI ATC Junior Executive 25 March 2021 Official Paper (Shift 2)
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  1. (12x- y2), (-4xy)
  2. (12x-2y2), (-2xy)
  3. (12x- y2), (-2xy)
  4. (6x- y2), (-2xy)

Answer (Detailed Solution Below)

Option 3 : (12x- y2), (-2xy)
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Detailed Solution

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Given:

V = x (y2 - 4x2)

Concept:

To calculate electric field from potential function, we use partial derivate wrt x, y and z respectively.

Formula:

Ex = -δV/δx,

Ey = -δV/δy,

Ez = -δV/δz

where δy/δx means partial derivative of y wrt x treating other variables as constant.

Calculation:

V = x (y2 - 4x2)

⇒ V = xy2 - 4x3  

• Ex = -δV/δx

⇒ Ex = \(-\frac{\delta(xy^2 - 4x^3) }{\delta x}\)

= -(y2 - 12x2)

12x2 - y2

• Ey = -δV/δy

⇒ Ex = \(-\frac{\delta(xy^2 - 4x^3) }{\delta y}\)

= -2xy

• Ez = \(-\frac{\delta(xy^2 - 4x^3) }{\delta z}\)

= 0

∴ Ex = 12x2 - y2, Ey = -2xy, Ez = 0

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