Question
Download Solution PDFকাঠের একটি ঘনকাকার খন্ডের কর্ণের দৈর্ঘ্য 192 সেমি। এর আয়তন নির্ণয় করো।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
কর্ণ (d) = 192 সেমি
ব্যবহৃত সূত্র:
d = a√3
যেখানে, a = ঘনকের বাহু
আয়তন (V) = a3
গণনা:
192 = a√3
⇒ a = \(\frac{192}{\sqrt{3}}\)
⇒ আয়তন = \(\left(\frac{192}{\sqrt{3}}\right)^3\)
⇒ আয়তন = \(\frac{192\times 192\times 192}{(3\sqrt{3})}\)
⇒ আয়তন = \(64\times 192\times 64\sqrt3\)
⇒ আয়তন = \(786432\sqrt3\)
∴ ঘনকাকার খন্ডটির আয়তন \(786432\sqrt{3}\) সেমি3।
Last updated on Jun 3, 2025
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