যদি 16 sec2 θ – 40 sec θ + 25 = 0  θ একটি সূক্ষ্মকোণ হয়, তাহলে tan θ এর মান কত হবে?

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NTPC CBT-I (Held On: 12 Jan 2021 Shift 1)
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  1. \(\frac{3}{4}\)
  2. \(\frac{4}{5}\)
  3. \(\frac{4}{3}\)
  4. \(\frac{3}{5}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{3}{4}\)
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RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
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Detailed Solution

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প্রদত্ত:

16 sec2 θ – 40 sec θ + 25 = 0

গণনা:

⇒ 16 sec2 θ – 40 sec θ + 25 = 0

⇒ 16 sec2 θ – 2 × 4 × 5 sec θ + 25 = 0

⇒ (4secθ - 5)2 = 0

⇒ 4secθ = 5

⇒ secθ = 5/4

তাহলে,

⇒ 1 + tan2θ = sec2θ

⇒ tan2 θ = 25/16 - 1 = 9/16

∴ tanθ = 3/4

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