Question
Download Solution PDFAn energy source forces a constant current of 5 ampere for 4 sec to flow through a light bulb. If 3 kJ given in terms of light energy, the voltage drop across the bulb is________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 1):(150 V)
Concept:
The charge which flows given by
where i is the current
Δt is time
The voltage drop across the bulb
V =
Δw is the energy
Calculation:
i = 5 A
Δt = 4 sec
Δw = 3000 J
q = 5 × 4 =20 C
V =
=
= 150 V
Last updated on May 8, 2025
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