An element from a strained material is subjected to 50 MPa and 100 Mpa (both tensile) in two mutually perpendicular directions. Then, the Major principal stress is:

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OSSC JE Civil Mains (Re-Exam) Official Paper: (Held On: 3rd Sept 2023)
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  1. 200 MPa
  2. 100 Mpa
  3. 150 Mpa
  4. 400 Mpa

Answer (Detailed Solution Below)

Option 2 : 100 Mpa
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Detailed Solution

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Concept:

In Normal and shear stress, the Magnitude of the stress is maximum for Surfaces that are perpendicular to a certain direction, & Zero Across any Surface that is Parallel.

Principle Stress:

The magnitude of Normal stress, acting on a principal plane is Known as Principal Stresses.

Calculation:

Given,

σx = 0

σy = 0

τxy = 0 MPa σmax =  50 MPa σmin = 100 MPa 

σmax = 75 + 25 = 100 MPa

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