Question
Download Solution PDFAn element from a strained material is subjected to 50 MPa and 100 Mpa (both tensile) in two mutually perpendicular directions. Then, the Major principal stress is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In Normal and shear stress, the Magnitude of the stress is maximum for Surfaces that are perpendicular to a certain direction, & Zero Across any Surface that is Parallel.
Principle Stress:
The magnitude of Normal stress, acting on a principal plane is Known as Principal Stresses.
Calculation:
Given,
\(σ_{max/min}=\frac{σ_{x}+σ_{y}}{2}\pm \sqrt{(\frac{σ_{x}-σ_{y}}{2})^{2}+τ _{xy}^{2}}\)
σx = 0
σy = 0
τxy = 0 MPa σmax = 50 MPa σmin = 100 MPa
\(σ_{max/min}=\frac{50+100}{2}\pm \sqrt{(\frac{50-100}{2})^{2}+0}\)
σmax = 75 + 25 = 100 MPa
Last updated on Jun 4, 2025
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